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Posted: **Thu Dec 05, 2019 4:42 pm**

I'am trying to run jar-file and it's working find if I'am not using variables like this

var status = Process.execute("java -jar C:/pdfboxer.jar -trimBox 55.94803135054997,56.82283454999998,1164.1039372989,765.3543309 -sourceFile C:/myfile.pdf -destFile C:/trimmed.pdf");

If I run the code below in SwitchScipter

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var status = Process.execute("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + sourceFile + " -destFile C:/trimmed.pdf");

or this code with getPath

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var status = Process.execute("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + job.getPath() + " -destFile C:/trimmed.pdf");

I get the java error that it can't open the file.

If log sourceFile I get the correct path and I can see the pdf file in the folder.

How do I use the incoming file as the soruce file?

Posted: **Thu Dec 05, 2019 11:20 pm**

Try entering "cmd /c " before "java ..."

Posted: **Fri Dec 06, 2019 9:35 am**

Try this instead

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var myJob = job.getPath();

And then

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var status = Process.execute("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + myJob + " -destFile C:/trimmed.pdf");

Posted: **Fri Dec 06, 2019 12:10 pm**

jan_suhr wrote: ↑Fri Dec 06, 2019 9:35 am Try this instead
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var myJob = job.getPath();
And then
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var status = Process.execute("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + myJob + " -destFile C:/trimmed.pdf");

You have just added a variable?

That is what I did with my second code snippet that is not working.

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var sourceFile = job.getPath();

var status = Process.execute("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + sourceFile + " -destFile C:/trimmed.pdf");

But I get the correct path in the log with this

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s.log(2, sourceFile);

Posted: **Fri Dec 06, 2019 12:14 pm**

Ok, wasn't obvious in your post.

Try this then.

(status)

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Process.execute(status)

Where Status is

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var status = ("java -jar " + scriptPath + " -trimBox "  + startX + "," + startY + "," + xmlWidth + "," + xmlHeight +  " -sourceFile " + myJob + " -destFile C:/trimmed.pdf");

Posted: **Tue Dec 10, 2019 2:36 pm**

job.getPath() will most likely contain spaces so you have to quote the value when using it on the command line:

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var myJob = "\"" + job.getPath() + "\"";

The same goes for any other file path on the command line.

Posted: **Fri Dec 13, 2019 3:05 pm**

freddyp wrote: ↑Tue Dec 10, 2019 2:36 pm job.getPath() will most likely contain spaces so you have to quote the value when using it on the command line:
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var myJob = "\"" + job.getPath() + "\"";
The same goes for any other file path on the command line.

WOW thanks it worked! So simple but hard to find.

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job.getPath() can't find the file

job.getPath() can't find the file

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